If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2-3x+4x^2-4=190
We move all terms to the left:
3x^2-3x+4x^2-4-(190)=0
We add all the numbers together, and all the variables
7x^2-3x-194=0
a = 7; b = -3; c = -194;
Δ = b2-4ac
Δ = -32-4·7·(-194)
Δ = 5441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{5441}}{2*7}=\frac{3-\sqrt{5441}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{5441}}{2*7}=\frac{3+\sqrt{5441}}{14} $
| 3x^2-3x=4x^2-4 | | 2x-2x=x-x-3 | | 13r+2r+2r-13r+3r=14 | | 3x^2-3x+4x^2-4=180 | | -33-7x=-3(-x+1) | | 2-16t=6(-3t+2( | | 3(8-3c)=4c-34 | | 4n-8(n+6)=-96 | | 3n+n-7=61 | | n/9.6=7/23.1 | | 3x^2+4x^2-4=180 | | 19d-16d=15 | | 6t-2=118 | | 0=49/50n+1/50n-n | | 7=f/3+6 | | a/4(a+5)3=27 | | 5x*x=-6 | | 0.1(10)-0.1x+x=0.3(10) | | -33-7x=3(-x+1) | | q-3.7/3=1.93 | | 11x-105=5 | | 2x+8=x^2-4 | | 10h+20=250 | | 7x+2(10x+1)=-6x+(7x-10) | | 1.38=w/3-2.62 | | 5x+1+4x-10=180 | | 7w-(7/2)=-(3/2)w-(4/3) | | 4z+8.54=16.54 | | -6+5x+5x=14 | | 0+10x=55+25 | | (3/4)x-4=26 | | 25h+50=575 |